an> + N 3 + N 4 + N 5 )/N 4 == (1/ k 3 ) + (1/ k 6 ) + (1/ k 8 ) +1 + k 10
1/X 5 = (N 1 span> + N 2 + N 3 + N 4 + N 5 )/N 5 = (1/ k 4 ) + (1/ k 7 ) + (1/ k 9 ) + (1/ k 10 ) +1
k 1 = e - ? G 1/RT , k 2 = e - ? G 2/RT , k i> 3 = e - ? G 3/RT , k 4 = e - ? G 4/RT , k 5 = e - ? G 5/RT , k 6 = e - ? G 6/RT ,
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