gn="justify"> R = 75%
. Ðîçì³ðè ïðèì³ùåíü. p align="justify"> Äîâæèíà = 16,6 ì.
Øèðèíà = 6ì.
Âèñîòà = 2,8 ì. p align="justify">. Ñò³íè. p align="justify"> Ñò³íè ç âåëèêèõ øëàêîáåòîííèõ áëîê³â ³ç çîâí³øí³ì ôàêòóðíèì øàðîì (? = 20-30 ìì, < span align = "justify">? = 1000 êã/ì 3 ). Òîâùèíà ñò³íè 600ìì. R 0 = 1,93 ì 2 × ãîä × ° Ñ/êêàë. Ê = 0,52 êêàë/ì 2 × ãîä × ° Ç
. Ïåðåêðèòòÿ. p align="justify"> Ãîðèùíå äåðåâ'ÿíå ïåðåêðèòòÿ ç íàêàòîì ç³ çá³ðíèõ êîìèøèòîâèõ ùèò³â ³ óòåïëþâà÷åì òðåïåëîì .. Êîíñòðóêòèâí³ øàðè äàíîãî ïåðåêðèòòÿ: óòåïëþâà÷, ìàñòèëî 20ìì, êîìèøèòîâèõ ùèò 100ìì, øòóêàòóðêà ïî äðàí³ 20ìì.Îáùàÿ òîâùèíà ïåðåêðèòòÿ 200ìì. R 0 = 1,52 ì 2 × ãîä × ° Ñ/êêàë. Ê = 0,66 êêàë/ãîä × ì 2 × ° Ç
. Ïîë. p align="justify"> Óòåïëåíèé ï³äëîãó.
. ³êíà. p align="justify"> ³êíà ïîäâ³éí³, â ê³ëüêîñò³ 8øò. , Ê = 2,3 êêàë/ãîä × ì 2 × ° Ñ.. Ñê = 1:16 ³êíà ñòàíäàðòí³, ðîçì³ð îäíîãî â³êíà 1 × 0,85 ì.
. Äâåð³. p align="justify"> Äâåð³ ïîäâ³éí³, â ê³ëüêîñò³ 2øò. ðîçì³ð îäí³º¿ äâåð³ 1,2 × 2,2 ì. Ê = 2 êêàë/ãîä × ì 2 < span align = "justify"> × ° Ñ.
. ʳëüê³...